Question 1129657
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You used the word "parameter" twice, once completely incorrectly and once in a very confusing way.  I presume you meant to say:  The area of a rectangle is 6000 square units and the perimeter is 340 units.  What are the measures of the length and width?  If English is a second language for you, please try to get help from someone more fluent before posting the next time.


Let *[tex \Large x] and *[tex \Large y] represent the dimensions of the rectangle.  Then:


Area = *[tex \Large xy] and Perimeter = *[tex \Large 2x\ +\ 2y].  Hence:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  xy\ =\ 6000]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  x\ +\ y\ =\ 170]


So


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  y\ =\ 170\ -\ x]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  x(170\ -\ x)\ =\ 6000]


Put the quadratic into standard form and solve for *[tex \Large x], then calculate *[tex \Large 170\ -\ x]
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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