Question 1129645
{{{1/m+2/(m+2)-3/(m-2 )}}}...........common denominator is {{{m(m+2)(m-2 )=m(m^2-4 )=(m^3-4m)}}}


{{{((m+2)(m-2 ) )/(m^3-4m )  +  2m(m-2 )/(m^3-4m ) -3m(m+2)/(m^3-4m )}}}


{{{(m^2-4  )/(m^3-4m)  + (2m^2-4m )/(m^3-4m ) -(3m^3+6m)/(m^3-4m )}}}


{{{(m^2-4   + 2m^2-4m  -3m^2-6m)/(m^3-4m )}}}


{{{( 3m^2-10m  -3m^2-4  )/(m^3-4m )}}}


{{{( cross(3m^2)-10m  -cross(3m^2)-4  )/(m^3-4m )}}}


{{{(-10m -4  )/(m^3-4m )}}}


{{{(-(10m + 4))/(-(4m - m^3) )}}}


{{{(10m + 4)/(4m - m^3) }}}