Question 1129643
For incompressible fluid flow, A1*v1 = A2*v2, where A and v are the areas and velocities in the two pipes
v1 = 2.7 m/s
A1 = 0.02 m^2
A2 = 2*0.038 m^2 = 0.076 m^2
Thus v2 = 2.7*0.02/0.076 = 0.71 m/s