Question 1129627

If the two equations happened to be linearly dependent, you'd really only have one equation with two unknowns.  In that scenario there are an infinite number of solutions.<br>

For example:

6x-8y = -4.2
12x-16y = -8.4

Here the 2nd equation is simply the first one multiplied by 2, hence they are linearly dependent, and in trying to solve, the best you can do is  say   y = (1/8) (4.2 + 6x),  for all x.