Question 102591




First convert the standard equation {{{4x+6y=12}}} into slope intercept form


*[invoke converting_linear_equations "standard_to_slope-intercept", 4, 6, 12, 2, 1]




Now let's find the equation of the line that is perpendicular to {{{y=(-2/3)x+2}}} which goes through (0,5)


*[invoke equation_parallel_or_perpendicular "perpendicular", "-2/3", "2", 0,5]