Question 1129536
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The range, *[tex \Large R], of a projectile with an initial velocity of *[tex \Large v_o] fired at an angle of *[tex \Large \varphi] is given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ R\ =\ \frac{(v_o)^2\,\sin(2\varphi)}{g}]


where *[tex \Large g] is the acceleration due to gravity.


Solving for *[tex \Large \varphi]:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \varphi\ =\ \frac{\sin^{-1}\(\frac{R\,\cdot\,g}{(v_o)^2}\)}{2}]


Plug in your numbers and do the arithmetic.  In the mks system, *[tex \Large g\ =\ 9.8\text{m/sec^2}]
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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