Question 102599
Let M = the first number.
Let N = the second number.
We know the sum is 70, so
{{{M + N = 70}}}
We also know the second number is 1 more than 2 times the first number, which we can express as
{{{N = 2M + 1}}}
Now use substitution and plug the second equation into the first.
{{{M + (2M +1) = 70}}}
Combine like terms
{{{3M + 1  = 70}}}
Subtract 1 from each side
{{{3M = 69}}}
Divide each side by 3
{{{M = 23}}}
Now we can plus this into the second equation.
{{{N = 2M + 1}}}
{{{N = 2 * 23 + 1}}}
{{{N = 46 + 1}}}
{{{N=47}}}
The two numbers are 23 and 47.
We can check this by plugging the numbers back into the first equation.
{{{M + N = 70}}}
{{{23 + 47 = 70}}}
{{{70=70}}}
Check.
That's all for this problem.