Question 1129437
Given that one of the dice has to be a 4, the other has to be a 2 (1/6 probability).
Same for this with 4-4
Probability a sum is 9 is 4/36 (3-6,6-3,4-5,5-4). If the question is given that the number cannot be a 4.  Given that a number is not 4, there are now 25 possible sums, and two of them are 9, 2/25 ANSWER

Given the sum is 5, there are 1-4,4-1,2-3,3-2, so given that the sum is 5, 1/2.

Probability is 1/2 that the exactly one of the dice shows a 1.  The exactly doesn't matter, since both dice can't be 1.