Question 1129312
A)
Let {{{ t }}} = yrs since 2010
slope = {{{ m }}}
{{{ m = ( 8700 - 12000 )/2 }}}
{{{ m = -3300/2 }}}
{{{ m = -1650 }}}
The vertical intercept must be {{{ 12000 }}}, since
that is the value when {{{ t=0 }}}
{{{ f(t) = -1650t + 12000 }}}
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B)
{{{ g(2) = 8700 }}}
{{{ 8700 = 12000*( 1 - r )^2 }}}
{{{ .725 = ( 1 - r )^2 }}}
{{{ 1 - r = sqrt( .725 ) }}}
{{{ 1 - r = .85147 }}}
{{{ r = .1485 }}}
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{{{ g(t) = 12000*( 1 - .1485 )^t }}}
check:
{{{ t = 2 }}}
{{{ g(2) = 12000*.85147^2 }}}
{{{ g(2) = 12000*.725 }}}
{{{ g(2) = 8700 }}}
OK