Question 1129328
{{{y=p*b^x}}}

y, amount present after x days
p, initial amount


{{{y=p*b^x}}}(


Half-life in days, 4.536
{{{1/2=b^4.536}}}

{{{log((1/2))=4.536*log((b))}}}

{{{log((b))=log((1/2))/4.536}}}


{{{b=0.8583}}}, each day 0.8583 fraction is retained;  0.1417 fraction is decayed.


14.17% decay per day.