Question 1129236


let {{{2}}} numbers be {{{x}}} and {{{y}}}

if they have the sum of {{{14}}},we have


{{{x+y=14}}} ....eq.1

 
and if they have the difference of {{{6}}}, we have

{{{x-y=6}}} ....eq.2


now, solve this system:

{{{x+y=14}}} ....eq.1
{{{x-y=6}}} ....eq.2
--------------------------------add both equations

{{{x+cross(y)+x-cross(y)=14+6}}} 

{{{2x=20}}} 

{{{x=10}}} 

now find {{{y}}}


{{{10+y=14}}} ....eq.1

{{{y=14-10}}} 

{{{y=4}}} 


so, your numbers are: {{{4}}} and {{{10}}}