Question 1129210
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#2.

<pre>
x^2 + 6x + 7 = (x^2 + 6x + 9) + 7 - 9 = (x^2 + 6x + 9) - 2 =


= {{{(x+3)^2}}} - 2 = {{{(x+3)^2}}} - {{{(sqrt(2))^2}}} = {{{(x+3-sqrt(2))}}}.{{{(x+3+sqrt(2))}}}.
</pre>


#3.

<pre>
2x^2  + 6x + 3 = (3x^2 + 6x + 3) - x^2 = 3*(x^+ 2x + 1) - x^2 = 


= {{{3*(x+1)^2}}} - {{{x^2}}} = {{{(sqrt(3)*(x+1))^2}}} - {{{x^2}}} = 


= {{{(sqrt(3)*(x+1)-x)*(sqrt(3)*(x+1)+x))}}} = {{{((sqrt(3)-1)*x+sqrt(3))*((sqrt(3)+1)*x+sqrt(3))}}}.
</pre>

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Do &nbsp;#1 &nbsp;in the same way as I did &nbsp;#3.