Question 1129189
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Both of the other two tutors used n, n+1, and n+2 (or x, x+1, and x+2) for the three consecutive integers.  If you are going to solve the problem with formal algebra, it is often easier (as in this case) to let the three integers be x-1, x, and x+1.  Then the algebra is a bit easier:<br>
{{{(x-1)+x+(x+1) = 195}}}
{{{3x = 195}}}
{{{x = 65}}}<br>
The three integers are x-1=64, x=65, and x+1=66.<br>
In this particular problem, using x-1, x, and x+1 for three consecutive integers only made the problem a bit easier to solve.  But in more complicated problems involving consecutive integers, it can make a big difference in the amount of work required to solve the problem.<br>
But note that this problem can be solved using informal logical reasoning MUCH faster than with formal algebra.  The exact same calculations are used; but you aren't slowed down with defining variables and solving equations.<br>
In any 3 consecutive integers, the middle one is the average of all three.  Since the sum is 195, the average is 195/3 = 65; then the 3 integers are 64, 65, and 66.