Question 1129199
Solve the system of equations:
Y=2x^2+3
Y=x+2
Enter one point as (x,y)
Enter two points as (x,y),(x,y)
Enter"no solution" as DNE.
<pre>There are solutions, but these are NOT THEY! 

{{{2x^2+3=x+2}}}
{{{2x^2-x+1=0}}}
{{{cross((2x+1)(x-1)=0)}}}


{{{cross(system(x=-1/2,or,x=1))}}}

<s>
points: ( -1/2, 3/2 ), ( 1, 3 )</s>

So, AGAIN, wait for someone who knows what they're doing to give you sensible, correct answers.
HINT: Correct answers are NON-REAL (IMAGINARY).