Question 1129131
Since the cards are drawn without replacement, there are 3 possibilities for 
the 1st number, 2 possibilities for the 2nd number and 1 possibility for the 
remaining number.
Thus, there are 3x2x1 = 6 combinations
Since the digits 2, 3 and 4 add up to 9, all the numbers are divisible by 9 
and therefore also divisible by 3.