Question 102528
Start with the given expression


{{{(x-9)(x-8)}}}


When you FOIL, you multiply the terms in this order:

F-First   (i.e. you multiply the first terms in each parenthesis which in this case are {{{x}}} and {{{x}}})
O-Outer   (i.e. you multiply the outer terms in each parenthesis which in this case are {{{x}}} and {{{-8}}})
I-Inner   (i.e. you multiply the inner terms in each parenthesis which in this case are {{{-9}}} and {{{x}}})
L-Last    (i.e. you multiply the last terms in each parenthesis which in this case are {{{-9}}} and {{{-8}}})



So lets multiply the first terms: 

{{{x*x=x^2}}}   multiply {{{x}}} and {{{x}}} to get {{{x^2}}}




So lets multiply the outer terms: 

{{{x*-8=-8x}}}   multiply {{{x}}} and {{{-8}}} to get {{{-8x}}}




So lets multiply the inner terms: 

{{{-9*x=-9x}}}   multiply {{{-9}}} and {{{x}}} to get {{{-9x}}}




So lets multiply the last terms: 

{{{-9*-8=72}}}   multiply {{{-9}}} and {{{-8}}} to get {{{72}}}


Now lets put all the multiplied terms together

 {{{x^2-8x-9x+72}}}


 Now combine like terms


 {{{x^2-17x+72}}}


 So the expression


 {{{(x-9)(x-8)}}}


 FOILs to:


 {{{x^2-17x+72}}}