Question 1128973
{{{8/(x-1)=n/(x^2+x-2)}}}


{{{8/(x-1)=n/((x-1)(x+2))}}}


{{{(8/(x-1))((x+2)/(x+2))=n/((x-1)(x+2))}}}


{{{highlight((8x+16)/((x-1)(x+2)))}}}=n/((x-1)(x+2))}}}