Question 1128977
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Let the two numbers be x and x+8; then the product is x^2+8x.<br>
The minimum value of a quadratic function ax^2+bx+c is when x = -b/2a; in this problem that is -8/2 = -4.<br>
So the two numbers are x=-4 and x+8 = 4; the minimum product is -16.