Question 102290
sorry, I don't think this is a "trick" question


if E were telling the truth, all the others would say the same ... E is a lying blue-eye AND there are <4 green-eyes


if A were telling the truth, at least one other would say the same ... A is a lying blue-eye AND there are <3 green-eyes and >2 blue-eyes


if B were telling the truth, then B is the only green-eye - BUT - that would mean C is a lying blue-eye, and C reports "1 pair of green eyes", which would be true


so B is a lying blue-eye 


C and D are truthful green-eyes