Question 1128923
<br>
The circular sheet is a very thin cylinder, with height 0.01 inches.<br>
Volume of lead ball (sphere): {{{(4/3)(pi)(r^3) = (4/3)(pi)(1^3) = (4/3)(pi)}}}<br>
Volume of circular sheet (cylinder): {{{(pi)(r^2)(h) = (pi)(r^2)(0.01) = 0.01(pi)r^2}}}<br>
The two volumes are the same:<br>
{{{(4/3)pi = 0.01(pi)r^2)}}}
{{{4/3 = 0.01r^2}}}
{{{r^2 = 400/3}}}
{{{r = sqrt(400/3)}}} = about 11.55 inches