Question 1128920
2   2 -1 -8 4
    2  3 -2 0
(x-2)(2x^2+3x-2)
=(x-2)(2x-1)(x+2)
zeros of 2 -2 and 1/2

{{{graph(300,300,-10,10,-10,10,2x^3-x^2-8x+4)}}}