Question 1128875
np=(140/6)=23.33 expected value
np(1-p)=(140/6)(5/6)=700/36 variance and sd is sqrt(V)=4.41
z=(27.5-23.33)/4.41, using 27.5 as the continuity correction factor for at most 27
z< +0.946
probability is 0.828
Normal distribution with mean 23.33 and sd 4.41
binomial includes 27 and up to 27.5.