Question 102510
{{{3x+6y=0}}}
{{{x=2/3}}}
Substituting the value 2/3 into the first equation, we have:
{{{3(2/3)+6y=0}}}, which simplifies to:
{{{2+6y=0}}}.
Subracting 2 from both sides, we have:
{{{6y=-2}}}.
Dividing through by 6:
{{{y=-2/6=-1/3}}}
Always check. So substitute x=2/3 and y=-1/3 back into the original equation:
{{{3(2/3)+6(-1/3)=2-2=0}}}. Check.