Question 1128873
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{{{2x*((1/2)x+1)}}} = {{{-2x - 5}}}


{{{x^2 + 2x}}} = {{{-2x - 5}}}


{{{x^2 + 4x + 5}}} = 0


{{{x[1,2]}}} = {{{(-4 +- sqrt(4^2 - 4*1*5))/2}}} = {{{(-4 +- sqrt(-4))/2}}} = {{{-2 +- sqrt(-1))}}} = -2 +- i.


{{{x[1]}}} = -2 + i;   {{{x[2]}}} = -2 - i.


The roots are found and presented in the requested form .
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Solved, answered and completed.



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