Question 1128862
{{{ f(x) >= g(x) }}}
{{{ 5x^2 >= 23x - 12 }}}
{{{ 5x^2 - 23x + 12 >= 0 }}}
{{{ ( 5x - 3 )*( x - 4 ) = 0 }}} ( I just guessed at this )
{{{ x >= 4 }}}
and
{{{ x >= 3/5 }}}
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{{{ x >=4 }}} is the solution that works here
This is the case where I have (+)*(+) = (+)
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Now (-)*(-) = (+)
{{{ x <= 3/5 }}} is the solution here
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{{{ 3/5 >= x >= 4 }}}