Question 1128801
{{{(x^2-4x+3) /(3-x)}}}...first factor numerator; write {{{-4x}}} as {{{-x-3x}}}

{{{(x^2-x-3x+3) /(3-x)}}}....group

{{{((x^2-x)-(3x-3)) /(3-x)}}}....factor out {{{x}}} from first group and {{{3}}} from second group

{{{(x(x-1)-3(x-1)) /(3-x)}}}


{{{((x-3)(x-1)) /(3-x)}}}..........factor out {{{-1}}} in denominator


{{{((x-3)(x-1)) /(-(x-3))}}}...simplify


{{{(cross((x-3))(x-1)) /(-cross((x-3)1))}}}


{{{-(x-1)}}}


{{{1-x}}}