Question 1128794
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Use the general formula:


    the distance from the point (p,q) to a straight line ax + by + c = 0  is

              d = {{{abs(ap + bq +c)/sqrt(a^2 + b^2)}}}.



Regarding this formula, see the lesson  <A HREF=https://www.algebra.com/algebra/homework/Vectors/The-distance-from-a-point-to-a-straight-line-in-a-coordinate-plane.lesson>The distance from a point to a straight line in a coordinate plane</A>  in this site.


In your case, the equation of the straight line is 2x + y - 3 = 0, so the distance is

    d = {{{abs(2*4 + 1*1 - 3)/sqrt(3^2+1^2)}}} = {{{6/sqrt(10)}}} = {{{(6*sqrt(10))/10}}} ~ 1.897367 (approximately).
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