Question 1128785

{{{(z^-4)^2/z^-6}}}


={{{(1/z^4)^2/(1/z^6)}}}


={{{(1/z^8)/(1/z^6)}}}


={{{z^6/z^8}}}


={{{cross(z^6)1/(cross(z^6)*z^2)}}}


={{{1/z^2}}}