Question 1128779
Simplify.  


{{{1/(n^-2*n^-4*n^-1)}}}


={{{1/((1/n^2)*(1/n^4)*(1/n^1))}}}



={{{1/(1/(n^2*n^4*n^1))}}}



={{{1/(1/(n^(2+4+1)))}}}



={{{1/(1/(n^7))}}}


={{{n^7/1}}}


={{{n^7}}}