Question 1128781

if you have this:

{{{1/2 = 2t-1/6 }}}

{{{1/2+1/6 = 2t }}}

{{{3/6+1/6 = 2t }}}

{{{4/6 = 2t }}}

{{{2/3 = 2t }}}

{{{(cross(2)1/3 )/cross(2)= t }}}

{{{t=1/3  }}}


in case you have:

{{{1/2 = (2t-1)/6 }}}

{{{1*6 = (2t-1)*2 }}}

{{{6 = 4t-2 }}}

{{{6+2 = 4t }}}

{{{8 = 4t }}}

{{{t = 2 }}}