Question 1128722
slope: {{{m= 2/5}}}
passes through ({{{-10}}},{{{-1}}})

use point-slope formula

{{{y-y[1]= m(x-x[1])}}}

{{{y-(-1)= (2/5)(x-(-10))}}}

{{{y+1= (2/5)(x+10)}}}

{{{y+1= (2/5)x+(2/cross(5))cross(10)2}}}

{{{y= (2/5)x+2*2-1}}}

{{{y= (2/5)x+4-1}}}

{{{y= (2/5)x+3}}}



{{{drawing (600, 600, -15, 15, -15, 15,
circle(-10,-1,.14), locate(-10,-1,p(-10,-1)),
graph(600, 600, -15, 15, -15, 15, (2/5)x+3)) }}}