Question 1128709
if you have a point  ({{{-2/3}}},{{{1}}}), you know that coordinate {{{x=-2/3}}} and coordinate {{{y=1}}}

to place it on a graph you first mark  {{{-2/3}}} on x-axis and  {{{1}}} on y-axis like this

{{{drawing( 600, 600, -5, 5, -5, 5,
circle(-2/3,0,.08),circle(0,1,.08),
 graph( 600, 600, -5, 5, -5, 5,0)) }}}

then, from {{{-2/3}}} on x-axis, draw a line parallel to y-axis
and from {{{1}}} on y-axis, draw a line parallel to x-axis

{{{drawing( 600, 600, -5, 5, -5, 5,
circle(-2/3,0,.08),circle(0,1,.08),
line(-2/3,2,-2/3,-2),line(-2,1,2,1),
 graph( 600, 600, -5, 5, -5, 5,0)) }}}

your point will be at intersection of these two lines


{{{drawing( 600, 600, -5, 5, -5, 5,
circle(-2/3,0,.08),circle(0,1,.08),circle(-2/3,1,.08),locate(-2/3,1,p(-2/3,1)),
line(-2/3,2,-2/3,-2),line(-2,1,2,1),
 graph( 600, 600, -5, 5, -5, 5,0)) }}}