Question 1128710


{{{x^2-16x+73=0}}} .........use quadratic formula

{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}......in your case {{{a=1}}},{{{b=-16}}}, and {{{c=73}}}

{{{x = (-(-16) +- sqrt( (-16) ^2-4*1*73 ))/(2*1) }}}

{{{x = (16 +- sqrt( 256-292 ))/2 }}}

{{{x = (16 +- sqrt(-36))/2 }}}

{{{x = (16 +- sqrt(-1*6^2))/2 }}}

{{{x = (16 +- sqrt(-1)*sqrt(6^2))/2 }}}

{{{x = (16 +- 6i)/2 }}}

{{{x = (16/2 +- 6i/2) }}}

{{{x = (8 +- 3i) }}}

solutions:

{{{x = 8 + 3i }}}

{{{x = 8 - 3i }}}