Question 1128677

{{{abs(2x - 3) < 1}}}

recall that is same as 

{{{sqrt((2x -3)^2) < 1}}}


solutions:

{{{2x -3 < 1}}}
{{{2x < 1+3}}}
{{{2x < 4}}}
{{{x < 2}}}

or

{{{-(2x -3) < 1}}}
{{{-2x +3 < 1}}}
{{{-1+3 < 2x }}}
{{{2< 2x }}}
{{{x>1}}}

=>

{{{1<x<2}}}

interval notation: ({{{1}}},{{{2}}})