Question 1128655

the equation of a circle satisfying the given conditions.
 
Center:({{{2}}}, {{{4}}}), radius: {{{sqrt(2)}}}

The center-radius form of the circle equation is in the format:

{{{ (x - h)^2 + (y - k)^2 = r^2}}}

{{{ (x-2)^2 + (y - 4)^2 = (sqrt(2))^2}}}

{{{ (x-2)^2 + (y -4)^2 = 2}}}

The equation of the circle in standard form is_{{{ (x-2)^2 + (y - 4)^2 = 2}}}__.