Question 1128581

Let {{{f(x)=x^2-1}}},  {{{x >=0}}}. 
{{{g(x)=sqrt (x-1)}}}

a) Find {{{(f*g)(x)}}}=>I guess you have {{{(f o g)(x)}}}

{{{(f o g)(x)= f(g(x))= ((sqrt (x-1))^2-1)=x-1-1=x-2}}}
b)

 Find {{{(g*f)(x)}}}-> {{{(g o f)(x)}}}

{{{(g o f)(x)= g(f(x))=sqrt ((x^2-1)-1)=sqrt (x^2-2)}}}