Question 1128591
{{{xy=12}}}
{{{y=12/x}}}



{{{x^2+4x-12=0}}}
{{{(x+6)(x-2)=0}}}
-
{{{x=-6,or,x=2}}}


Corresponding intersection points:
(-6,-2) and (2, 6).


The line for these points:
slope  {{{(6-(-2))/(2-(-6))=1}}};
{{{y-6=x-2}}}

{{{highlight_green(y=x+4)}}}



{{{graph(400,400,-8,8,-8,8,12/x,x+4)}}}