Question 1128404
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<pre>

For a disk of mass  M  and radius  R,  the moment of inertia  I  is

    I = {{{1/2}}}.{{{M*R^2}}}.


If the disk is spinning with angular speed  {{{alpha}}} radians per second, its rotational kinetic energy is
    
    K.E. = {{{(1/2)*I*alpha^2}}} = {{{(1/2)*(1/2)*M*R^2*alpha^2}}} = {{{1/4}}}.{{{M*R^2*alpha^2}}}.
</pre>


What you need to do now is to substitute your data; to take your calculator and to complete calculations on your own.


Be sure to have the mass in kilograms and the radius in meters.



The reference is this link.


https://www.unr.edu/Documents/science/physics/labs/180/11_Rotational_Kinetic_Energy.pdf