Question 1128578
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(1) Don't use a decimal approximation for the number of hours.  Use 5/3 hours.<br>
(2) Time is distance divided by speed -- not speed divided by distance.<br>
(3) The greater time is at the lower speed; the the 5/3 hours difference is (time at lower speed) minus (time at higher speed).  You have the two expressions in the wrong order in your equation.<br>
So....<br>
{{{300/(x-15) - 300/x = 5/3}}}<br>
Multiply everything by the common denominator, x(x-15); and multiply everything by 3/5 to get rid of the fraction on the right.<br>
That will give you the quadratic equation which you can solve by completing the square.