Question 1128540


{{{V = Bh / 3 }}}

{{{V = 208cm^2}}}

{{{x + 2}}} is width of one of the bases
{{{x}}} is length of the other base 
{{{h=3cm}}}


 {{{208 = ((x+2)x*13) / 3 }}}

 {{{208 = ((x+2)x*13) / 3 }}}

 {{{(3*208c)/13 = (x+2)x }}}

{{{48 = x^2+2x }}}

{{{ x^2+2x- 48=0}}}

{{{ (x - 6) (x + 8) = 0}}}

we need only positive solution:

{{{ (x - 6)  = 0}}}->{{{x=6}}}

{{{x + 2=8}}} is width of one of the bases
{{{x=6}}} is length of the other base