Question 1128547


Note that {{{a^2 + b^2 = c^2 }}}


{{{a= x}}} ft
{{{b= (x+1)}}} ft
{{{c= (x+2)}}} ft

{{{x^2 + (x+1)^2 = (x+2)^2 }}}

{{{x^2 + x^2+2x+1 = x^2+4x+4 }}}

{{{x^2 + cross(x^2)+2x+1 -cross(x^2)-4x-4=0 }}}

{{{x^2 -2x-3=0 }}}

{{{x^2+x -3x-3=0 }}}

{{{(x^2+x) -(3x+3)=0 }}}

{{{x(x+1) -3(x+1)=0 }}}

{{{(x -3)(x+1)=0 }}}

{{{(x -3)=0 }}}->{{{x=3}}}-> we need only positive solution (the length)

{{{(x+1)=0 }}}->{{{x=-1}}}


{{{a=3}}} ft
{{{b= (x+1)=4}}} ft
{{{c= (x+2)=5}}} ft