Question 102479
Four consecutive odd integers named W,X,Y, and Z have the following relationship.  
{{{W = W}}}
{{{X = W + 2 }}} 
{{{Y = X + 2 = (W+2) + 2 = W + 4 }}}
{{{Z = Y + 2 = (W+4) + 2 = W + 6 }}}
Their sum equals 216.
{{{W+X+Y+Z=216}}}
{{{W+(W+2)+(W+4)+(W+6)=216}}}Substitute.
{{{4*W+12=216}}}Simplify.
{{{4*W+12-12=216-12}}}Additive Inverse of 12.
{{{4*W=204}}}Simplify.
{{{4*W/4=204/4}}}Multiplicative Inverse of 4. 
W=51
X=53
Y=55
Z=57
Check your answer
{{{51+53+55+57 = 216}}}
{{{216 = 216}}}
Good answer.