Question 1128504
1.4m^2+10m-5=0
2.(y+3) (y-5) =2y-2
3.4m^2=(m+4) (2-m)... for all using completing the square method.... thank you.. 
<pre>1. {{{matrix(1,3, 4m^2 + 10m - 5, "=", 0)}}}
   {{{matrix(1,3, 4m^2/4 + (10/4)m - 5/4, "=", 0/4)}}} ----- Dividing by 4 to make LEADING COEFFICIENT, + 1.
   {{{matrix(1,3, m^2 + (5/2)m, "=", 5/4)}}} ---------- Reducing fraction and ADDING {{{5/4}}}
  {{{matrix(1,3, m^2 + (5/2)m + ((1/2) * (5/2))^2, "=", 5/4 + ((1/2) * (5/2))^2)}}} ------ Taking {{{1/2}}} of "b," SQUARING it, and then ADDING the result to both sides
    {{{matrix(1,3, m^2 + (5/2)m + (5/4)^2, "=", 5/4 + (5/4))^2)}}}
    {{{matrix(1,3, (m + 5/4)^2, "=", 5/4 + 25/16)}}}
    {{{matrix(1,3, (m + 5/4)^2, "=", 20/16 + 25/16)}}}
    {{{matrix(1,3, (m + 5/4)^2, "=", 45/16)}}}
    {{{matrix(1,3, sqrt((m + 5/4)^2), "=", " "+- sqrt(45/16))}}} ----- Taking square root of both sides
    {{{matrix(1,3, m + 5/4, "=", " "+- 3sqrt(5)/4)}}}
    {{{highlight_green(matrix(1,6, m, "=", " "+- 3sqrt(5)/4 - 5/4, ",", or, " "+- (3sqrt(5) - 5)/4))}}}

You can calculate that if you need APPROXIMATE solutions.
Now, you need to try the others on your own!</pre>