Question 1128505
{{{12^((x+2))=72 }}}
using common logs
{{{log(12^((x+2)))=log(72) }}}
log equiv of exponents
(x+2)log(12) = log(72)
x + 2 = {{{log(72)/log(12)}}}
use your calc
x + 2 = 1.721
x = 1.721 - 2
x = -.279
:
:
Confirm with your calc enter 12^(-.279+2) ~ 72.0