<PRE><B>Question 1128494</B>
&lt;br&gt;
Apparently this question is from a course you are taking.  Our giving you the answer won&#39;t help you learn anything; and presumably learning something is your objective in taking the course.&lt;br&gt;
It would help us help you if, as you are asked to when you post your question, you told us what you tried to do on the problem.&lt;br&gt;
Algebraically, if x is the car&#39;s speed, then the number of hours taken to drive 560 miles is 560/x.  The number of hours to travel the same 560 miles at a speed 10mph faster would be 560/(x+10).  And the second time is 1 hour less than the first:&lt;br&gt;
{{{560/(x+10) = 560/x-1}}}&lt;br&gt;
Multiply through by the least common denominator of all the fractions, x(x+10):&lt;br&gt;
{{{560x = 560(x+10)-x(x+10)}}}
{{{560x = 560x+5600-x^2+10x}}}
{{{x^2-10x-5600 = 0}}}&lt;br&gt;
Factor into the form (x+?)(x-?) to finish the problem.&lt;br&gt;
I hope you have learned enough from the course that you can do that....&lt;br&gt;
If you can&#39;t finish, then try finding the answer by logical guess-and-check.  Presumably this is a computer based question, and only an answer is needed; it doesn&#39;t matter how you get the answer.  (Well... if you want to learn from the course, it matters; but if you just need the right answer, you can guess it.)&lt;br&gt;
You need two numbers -- a reasonable highway speed in mph and a reasonable number of hours -- whose product is 560.  Then you need another speed 10mph faster and another number of hours that is 1 less, whose product is again 560.&lt;br&gt;
A little playing with &quot;nice&quot; numbers should allow you to guess the answer to the problem.</PRE>