<PRE><B>Question 1128471</B>
 How many liters of a 20% alcohol solution should be added to a 10% alcohol solution to create a 50 ml solution that is 15 % alcohol? 
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Equation::
alch + alch = alch
0.20x + 0.10(50-x) = 0.15*50
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20x + 10*50-10x = 15*50
10x = 5*50
x = 25 liters (amt. of 20% solution needed)
50-x = 25 liters (amt. of 10% solution needed)
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Cheers,
Stan H.
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