Question 1128478
an equation in slope-intercept form for the line:

{{{y=mx+b}}} where {{{m}}} is a slope and {{{b}}} is y-intercept 


if line is perpendicular to the graph of the line {{{y=3x+5}}}, its slope must be negative reciprocal of the {{{3}}} (which is a slope of the given line) and it is:

{{{m=-1/3}}}

so far, equation of the perpendicular line is:

{{{y=-(1/3)x+b}}}


if the line passes through ({{{-1}}},{{{4}}}),we will use it to find  {{{b}}}

{{{4=-(1/3)(-1)+b}}}

{{{4=(1/3)+b}}}

{{{b=4-(1/3)}}}

{{{b=11/3}}}


{{{y=-(1/3)x+11/3}}}=> your answer



{{{drawing( 600, 600, -15, 15, -15, 15,
circle(-1,4,.17),locate(-1.3,4.3,p(-1,4)),
 graph( 600, 600, -15, 15, -15, 15, 3x+5, -(1/3)x+11/3)) }}}