Question 1128458


{{{g(x) = 8x^2 + 1}}},find the following:


{{{g(3) = 8*3^2 + 1=8*9+1=72+1=73}}}

{{{g(-1) =8*(-1)^2 + 1=8*1+1=8+1=9}}}

{{{g(0)=8*0+1=0+1=1}}}

{{{g(1/2)=8*(1/2)^2 + 1=8*(1/4)+1=2+1=3}}}

{{{g(c)=8c^2 + 1}}}

{{{g(c + 5) =8(c+5)^2 + 1=8(c^2+10c+25)+1=8c^2+80c+200+1=8c^2+80c+201}}}