Question 1128368
f 5 is added to the square of an integer, the result is 4 less than 10 times that integer. 
Find the integer(s).
:
write just what it says
x^2 + 5 = 10x - 4 
Arrange as a quadratic equation
x^2 - 10x + 5 + 4 = 0
x^2 - 10x + 9 = 0
factors easily to
(x-9)(x-1) = 0
Two solutions
x = 9
x = 1
:
You can check both solutions in the original equation