Question 1128296
To find the first four terms of the sequence whose {{{n^th}}} term (meaning the term number n) is given by
{{{a[n]=3n}}}
we simply substitute the first four counting numbers for {{{n}}} in that formula.
By "counting numbers, I mean 1, 2, 3, ....., and the first four are 1, 2, 3, and 4.
For {{{n=1}}} , we have
{{{a[1]=3*1=highlight(3)}}}
For {{{n=2}}} , we have
{{{a[2]=3*2=highlight(6)}}}
For {{{n=3}}} , we have
{{{a[3]=3*3=highlight(9)}}}
For {{{n=4}}} , we have
{{{a[4]=3*4=highlight(12)}}}